What are the roots of the equation 3X2-X 20?

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Answer

1065186

2026-08-04 21:50

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3x^2 - x + 20 = 0 doesn't factor neatly. Using the quadratic formula, we find two complex roots with imaginary solutions.

(1 plus the square root of -239) divided by 6

(1 minus the square root of -239) divided by 6

x = 0.16666 repeating + 2.576604138956718i

x = 0.16666 repeating - 2.576604138956718i

where i is the square root of negative one.

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