The test scores of a geometry class are given below. 90 75 72 88 85 The teacher wants to find the variance for the class population. What is the value of the numerator of the calculation of the?

To find the numerator of the variance for the class population, first calculate the mean of the test scores: (90 + 75 + 72 + 88 + 85) / 5 = 82. The numerator is the sum of the squared differences between each score and the mean. Calculating these differences: (90 - 82)² = 64, (75 - 82)² = 49, (72 - 82)² = 100, (88 - 82)² = 36, (85 - 82)² = 9. Adding these squared differences gives 64 + 49 + 100 + 36 + 9 = 258. Thus, the value of the numerator is 258.