To factor the expression (2x^2 + 6x - 13), we can look for two numbers that multiply to (2 \times -13 = -26) and add to (6). These numbers are (13) and (-2). Rewriting the expression, we have (2x^2 + 13x - 2x - 13) which can be grouped and factored as ((2x - 1)(x + 13)). Thus, the factorization of the expression is ((2x - 1)(x + 13)).
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