Find the length and width of a rectangular lot with a perimeter of 70 meters if the length is 5 meters more than the width?

Perimeter is 70, length is width + 5 so 2L + 2W = 70 and L = W + 5. So 2 (W + 5) + 2W = 70 ie 2W + 10 + 2W = 70 ie 4W = 70 - 10 ie 4W = 60 ie W = 15 and L = 20 Alternative method: L + W = 35, L = W + 5 W + 5 + W = 35 2W = 30, W =15