The real-world answer is that the bulb glows with dazzling brilliance for a few
seconds and then burns out.
Electrically, the technical answer is:
Assuming we're working with a traditional incandescent bulb, the filament is designed
to dissipate 25W when connected to 220V. We could easily calculate the resistance of
the filament from that information, but for this discussion, it doesn't matter. It's just 'R'.
The Power dissipated by anything is V2/R
So if the voltage across the device is doubled, the power dissipation increases by
a factor of 4 . Your incandescent bulb begins to dissipate 100w instead of 25w.
Refinement:
The resistance of any metallic conductor increases when the temperature of the
conductor rises. The temperature of the filament certainly increases when its
power dissipation increases.
So 'R' increases, and the dissipation settles at something a little less than 100
watts. But have no fear ... at 100% over-voltage, your bulb will definitely blow.
Copyright © 2026 eLLeNow.com All Rights Reserved.