What is a result of shifting a circle with equation x 32 y - 22 36 left 3 units?

Shifting the circle with the equation ( x^2 + y^2 - 22x - 36 = 0 ) left by 3 units involves adjusting the ( x ) coordinate in the equation. The new equation becomes ( (x + 3)^2 + y^2 - 22(x + 3) - 36 = 0 ). This results in a new center for the circle, which is now located at ( (19, 0) ) instead of ( (22, 0) ), while the radius remains unchanged. Thus, the overall shape and size of the circle do not change, only its position.