If you throw a 0.1 kg ball straight up with an initial speed of 29 ms how high will it climb?

To find the maximum height reached by the ball, you can use the kinematic equation (v_f^2 = v_i^2 + 2aΔy) where (v_f = 0), (v_i = 29 m/s), (a = -9.8 m/s^2) (acceleration due to gravity), and solve for (Δy). Substituting the values gives (0 = 29^2 - 29.8Δy), solving for Δy gives Δy ≈ 42 meters.