Is 10534341 divisible by 9 and 3 and 2?

To determine if 10534341 is divisible by 9, add the digits (1+0+5+3+4+3+4+1 = 21); since 21 is divisible by 9, the number is divisible by 9. For divisibility by 3, the sum of the digits (21) is also divisible by 3. However, for divisibility by 2, the number must be even, and since 10534341 ends in 1, it is not divisible by 2. Therefore, 10534341 is divisible by 9 and 3, but not by 2.