Since Luis can only pass or fail his test, and we know that the probability of all possible outcomes is 1, we therefore see that P(Pass) + P(Fail) = 1
*where P(X) = the probability of event X*
So if P(Pass) = .33;
then P(Fail) = 1 - P(Pass)
= 1 - .33
= .66 (or 66% chance that Luis will fail)
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