What are the solutions of 2x2 8x -26?

To solve the quadratic equation (2x^2 + 8x - 26 = 0), we can first simplify it by dividing all terms by 2, resulting in (x^2 + 4x - 13 = 0). Next, we apply the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}), where (a = 1), (b = 4), and (c = -13). This yields (x = \frac{-4 \pm \sqrt{16 + 52}}{2} = \frac{-4 \pm \sqrt{68}}{2} = \frac{-4 \pm 2\sqrt{17}}{2}), which simplifies to (x = -2 \pm \sqrt{17}). Thus, the solutions are (x = -2 + \sqrt{17}) and (x = -2 - \sqrt{17}).