If 1176 grams of FeS2 is allowed to react with 704 grams of O2 according to the following equation how many grams of Fe2O3 are produced?

First, balance the equation: 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. Calculate the moles of each reactant: moles FeS2 = 1176 g / molar mass of FeS2, moles O2 = 704 g / molar mass of O2. Identify the limiting reactant based on the stoichiometry of the reaction, then use stoichiometry to calculate the grams of Fe2O3 produced.