What is the molarity of 0. 96 g MgCl2 in 500 ml of solution?

To find the molarity of MgCl₂, first calculate the number of moles of MgCl₂ in 0.96 g. The molar mass of MgCl₂ (Mg: 24.31 g/mol, Cl: 35.45 g/mol × 2) is approximately 95.21 g/mol. Thus, moles of MgCl₂ = 0.96 g / 95.21 g/mol ≈ 0.0101 moles. Since the volume of the solution is 500 ml (0.5 L), the molarity (M) is calculated as moles/volume = 0.0101 moles / 0.5 L = 0.0202 M.