How much energy is required to raise the temperature of 3 kg of lead from 15 to 20 degrees of celsius?

To calculate the energy required to raise the temperature of a substance, we use the formula: Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. The specific heat capacity of lead is 0.128 J/g°C. Converting the mass to grams (1 kg = 1000 g), we have m = 3000 g. Plugging in the values, we get Q = 3000g * 0.128 J/g°C * (20°C - 15°C) = 1920 Joules. Therefore, 1920 Joules of energy is required to raise the temperature of 3 kg of lead from 15 to 20 degrees Celsius.