A juggler tosses three balls alternately vertically upward. each ball has an initial velocity of 10ms. how high does each ball rise how long does each ball remain in air?

Each ball rises to a height of 5 meters, given by the equation h = (v^2)/(2g), where v is the initial velocity (10 m/s) and g is the acceleration due to gravity (9.81 m/s^2). The time each ball remains in the air is approximately 1 second, calculated using the equation t = 2(v/g).