To find the probability that a randomly selected Timely brand watch will last longer than a certain time, we first need to convert the time into the same unit as the standard deviation. Since the mean is 4 years (or 48 months) and the standard deviation is 8 months, we can use the z-score formula ( z = \frac{(X - \mu)}{\sigma} ) where ( X ) is the time in months, ( \mu ) is the mean (48 months), and ( \sigma ) is the standard deviation (8 months). After calculating the z-score, we can look up the corresponding probability in the standard normal distribution table to find the likelihood of a watch lasting longer than that specified time. Please provide the specific time in months or years for a complete answer.
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