When a circuit has an inductor with an inductive reactance of 230 Ohms. This inductor is in series with a 500 Ohm resistor. If the source voltage is 24 V what is the total circuit current?

To find the total circuit current, first calculate the total impedance (Z) of the circuit. The total impedance in a series circuit with a resistor (R) and an inductor (X_L) is given by ( Z = \sqrt{R^2 + X_L^2} ). Substituting the values, we get ( Z = \sqrt{500^2 + 230^2} \approx 548.25 , \text{Ohms} ). Then, using Ohm's law (( I = \frac{V}{Z} )), the total circuit current is ( I = \frac{24}{548.25} \approx 0.0437 , \text{A} ) or 43.7 mA.