How do you draw a hexagon that has 2 right angles 2 acute and 2 obtuse?

If 1 or 2 of the obtuse angles are 'bent into' the hexagon then you can do it.

A hexagon has 720° sum of interior angles. If you have 2 right angles, then that's 180°, leaving 540° to be distributed over four angles. If the two acute angles are 89°, then that leaves 362° to be divided between two angles, so at least one of these two angles will need to be greater than 180°. Below is my text graphics attempt of one possibility (ignore the 'dot'). Note that both of the obtuse angles are greater than 180°:

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Look at the related link to play with different angle possibilities for polygons.