In triangle abc the measure of angle b is 4 degrees more than three times the measure of angle a the measure of angle c is 41 degree more than the measure of angle a find the measure of each angle?

given b = 3a + 4 and c = 41 + a, we also know that a + b + C = 180 in a triangle putting the values of b and c from above a + (3a + 4) + (41 + a) = 180 a + 3a + a + 4 + 41 = 180 5a + 45 = 180 5a = 180 - 45 = 135 a = 135 / 5 = 27, now putting the values of a b = 3 * 27 + 4 = 81 +4 = 85, and c = 41 +27 = 68.