A 1.0 mol sample of gas is contained in a 2.0L container at 1000 K What is the pressure exerted by this gas?

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Answer

1074272

2026-07-20 12:10

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Using the Ideal Gas Equation

PV = nRT

Algebraically rearranging

P = nRT / V

P = 1.0 * 8.314 * 1000/ 2.0

P = 4157 Pa = 4.157 kPa.

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