If there was a total of 10 bicycles and 10 tricycles and the total number of wheels was 23 how many were bicycles and how many were tricycles?

Let the number of bicycles be ( b ) and the number of tricycles be ( t ). We have two equations: ( b + t = 10 ) and ( 2b + 3t = 23 ). Solving these, substituting ( t = 10 - b ) into the second equation gives ( 2b + 3(10 - b) = 23 ), which simplifies to ( 10 - b = 23 ) leading to ( b = 7 ) and ( t = 3 ). Therefore, there are 7 bicycles and 3 tricycles.