Infinitely many.
Select any number between 0 and sqrt(28) and call it W.
Then let L = 28/W.
A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.
Select any number between 0 and sqrt(28) and call it W.
Then let L = 28/W.
A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.
Select any number between 0 and sqrt(28) and call it W.
Then let L = 28/W.
A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.
Select any number between 0 and sqrt(28) and call it W.
Then let L = 28/W.
A rectangle with length L units and width W units will have an area of LxW = (28/W)*W = 28 square units. And, since W could be any one of infinitely many numbers between 0 and sqrt(28), there are infinitely many possible answers.
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