What is the derivative of 2x-squared plus 4x plus 8?

y = 2x^(2) + 4x + 8

dy.dx = 2(2)x^(2-1) + 4x^(1-1) +8x^(0)

dy/dc = 2(2)x^(1) + (1)4x^(0) + (0)8x^(0-1)

dy/dx = 4x + 4 + 0

dy/dx = 4x + 4 *The derivative).

NB

#1 The original index number becomes a coefficient ( in brackets). Then subtract '1' from the original index value, for the new index value.

#2 Any term raised to the power of '0' = 1.

#3 Any term multiplied by '0' = 0.