The equation you provided seems to be missing some elements, but if we assume it is in the form ( y = a(x - h)^2 + k ), where ( (h, k) ) is the vertex, the vertex can be identified directly from the equation. For the equation ( y = (x - 1)^2 + 3 ), the vertex is ( (1, 3) ). If you meant something different, please clarify the equation for a more accurate answer.
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