If you have eight balls all of the same size.seven of them weigh the sameand one of them weighs slightly more.How can you find the ball that is heaviest in least amount of attempts?

One way to find the heaviest ball in two attempts is to split the balls into two groups of 4 each and weigh them against each other. Whichever group is heavier will contain the heavier ball. Then, take the heavier group of 4 balls and weigh two of the balls against each other. If one ball is heavier, it will be the heaviest ball. If they weigh the same, the third ball left out is the heaviest.