Evaluate 2(4h and minus5) and minus6 plus h for h and minus2.?

To evaluate (2(4h - 5)) and (-6 + h) for (h = -2), we first substitute (-2) for (h) in both expressions.

For (2(4(-2) - 5)): [ 2(4 \times -2 - 5) = 2(-8 - 5) = 2(-13) = -26 ]

For (-6 + (-2)): [ -6 - 2 = -8 ]

Thus, the evaluations give (-26) and (-8).