If K 5 and (4K plus 6) 26 and (6k-2) 28 for what value of k will they have the same length?

To find the value of ( k ) for which ( 4K + 6 = 26 ) and ( 6k - 2 = 28 ), we can solve each equation.

1. For ( 4K + 6 = 26 ): [ 4K = 20 ] [ K = 5 ]

2. For ( 6k - 2 = 28 ): [ 6k = 30 ] [ k = 5 ]

Both equations yield ( k = 5 ). Thus, when ( k = 5 ), both expressions have the same length.