Find the power dissipated by an 8.2k resistor if a current of 0.005 amps is passing through the resistor?

0.205 W

Power is equal to voltage times current (P=V*I) in Watts, and from Ohm's Law, the voltage across a capacitor is equal to the current passing through it times the resistance (V=I*R). The power is then P=I2R. For a current of 5mA and a resistance of 8.2kOhms, (5*10-3A)2*(8.2*103Ohms) = 0.205 W.