To determine the nature of the solution with 29.5 g of NaCl in 75.0 g of water at 25°C, we calculate the solubility ratio. Since 36.2 g of NaCl can dissolve in 100 g of water, the maximum amount that can dissolve in 75.0 g of water is approximately 27.15 g. Since 29.5 g exceeds this amount, the solution is supersaturated.
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