How many calories are required to melt 200 grams of ice at 0C and raise the temperature of the water from 0C to 75C?

here , you multiply the the mass of the ice times the latent heat of fusion so the answer is

5*3.33*(10^5)*(10^-3)=1665 Joule

so to convert the result into calories divide by 4.186(1 calorie -------------->4.186 Joule)

the result is : 397.75 Calorie