What is the power dissipated by a 9 ohm resistor with 3 amps flowing through it?

Here are a few easy and related equations.

V = Voltage, I = Current (amps)

R = Resistance, (Ohms)

V = I X R

R= V / I

I = V / R

Power = Watts = W, is expressed as V X I. Since V =I X R, W then also = R X I X I

Which is I **2 X R

Same as V**2 / R

So, if your I = 3 and your R = 3, and because I X R = V,

3 X 3 =9 Volts

(Note: capacitance and inductance can also influence the amount of current flow in a system. This resistance is referred to as reactance. Both reactances are a function of the frequency of the Voltage applied.)

Have a wonderful day. Bob