What is the sum of all two digit numbers divisible by 2?

The two-digit numbers divisible by 2 range from 10 to 98. This forms an arithmetic series where the first term (a) is 10, the last term (l) is 98, and the common difference (d) is 2. The number of terms (n) in this series can be calculated as ( n = \frac{l - a}{d} + 1 = \frac{98 - 10}{2} + 1 = 45 ). The sum of the series is given by the formula ( S_n = \frac{n}{2} (a + l) = \frac{45}{2} (10 + 98) = 2430 ).