What is the force on a 1000 kg elevator that is falling freely at 9.8 msec2?

The force acting on the elevator is equal to its weight, which can be calculated using the formula F = m * g, where m is the mass of the elevator (1000 kg) and g is the acceleration due to gravity (9.8 m/s^2). So, the force on the elevator would be 1000 kg * 9.8 m/s^2 = 9800 N.