What is the vertex of the graph of the function below y x2 plus 6x plus 5?

To find the vertex of the quadratic function ( y = x^2 + 6x + 5 ), we can use the vertex formula ( x = -\frac{b}{2a} ). Here, ( a = 1 ) and ( b = 6 ), so ( x = -\frac{6}{2 \cdot 1} = -3 ). To find the ( y )-coordinate, substitute ( x = -3 ) into the equation: ( y = (-3)^2 + 6(-3) + 5 = 9 - 18 + 5 = -4 ). Therefore, the vertex is at the point ((-3, -4)).