To determine how many days it takes for 16 g of palladium-103 to decay to 1.0 g, we first need to know its half-life, which is approximately 17 days. The decay from 16 g to 1.0 g represents a reduction by a factor of 16, which corresponds to 4 half-lives (since (2^4 = 16)). Therefore, it would take (4 \times 17 = 68) days for 16 g of palladium-103 to decay to 1.0 g.
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