What is the molar its of an aqueous solution containing 40.0 G of glucose in 1.5 L of solution?

To calculate the molarity (M) of the aqueous solution, you first need to determine the number of moles of glucose. The molar mass of glucose (C₆H₁₂O₆) is approximately 180.18 g/mol. Therefore, 40.0 g of glucose is equivalent to ( \frac{40.0 , \text{g}}{180.18 , \text{g/mol}} \approx 0.222 , \text{mol} ). The molarity is then calculated by dividing the number of moles by the volume of the solution in liters: ( M = \frac{0.222 , \text{mol}}{1.5 , \text{L}} \approx 0.148 , \text{M} ).