Ok, First you find the gradient using the formula: Y2-Y1/X2-X1
8-9 1
---- which is equal to: --- Which is the gradient (Answer to your question)
2-5 3
So now the equation becomes y=1/3x+c
To find the c (the Y intercept, you substitute one of the points into the equation.
I will use points (2,8)
So: 8=1/3(2)+c
8=2/3+c
c=(2/3)-8
c=-(22/3)
1 22
Therefore the equation of the line is: Y= --- x + - -----
3 3
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