What is the area of the rectangle with the width of a rectangle is 5 feet and the diagonal is 9 feet?

Pythagorean Theorem: a2+b2=c2 c=diagonal, a and b are side lengths for a right triangle (a rectangle is basically two right triangles) 92=52+a2 a2=92-52 a=~7.48 feet 7.48 feet*5 feet = 37.41 feet = the area of the rectangle