ABCD is a gm and X is the mid-pint of AB. If Ar.(AXCD)24cm2 find Ar. of ABCD?

To find the area of quadrilateral ABCD, we can use the property of midpoints in geometry. Since X is the midpoint of AB, the area of triangle AXC is half of the area of triangle ABC. Therefore, if the area of AXCD is 24 cm², then the area of triangle ABC is also 24 cm². Thus, the total area of quadrilateral ABCD, which consists of triangles AXC and BXC, is 48 cm² (24 cm² + 24 cm²).