How much work must be done on a 10 kg bicycle to increase its speed form 5 ms to 10 ms?

The work done on the bicycle is equal to the change in kinetic energy. The change in kinetic energy is given by 1/2 * m * (vf^2 - vi^2), where m is the mass of the bicycle, vf is the final velocity, and vi is the initial velocity. Plugging in the values, the work done is 625 J.