How much energy is required to melt 2 kg of gold in the equation qmlfusion?

To calculate the energy required to melt 2 kg of gold, you can use the equation ( q = m \cdot L_f ), where ( q ) is the heat energy, ( m ) is the mass, and ( L_f ) is the latent heat of fusion. The latent heat of fusion for gold is approximately 64.5 kJ/kg. Thus, for 2 kg of gold, the energy required would be ( q = 2 , \text{kg} \times 64.5 , \text{kJ/kg} = 129 , \text{kJ} ).