When two 4-ohm resistors are connected in parallel across 12 volts:
-- Each resistor has 12V across it, so the current is I = E/R = 12/4 = 3 amperes.
-- The total current from the battery is 6 amperes.
-- The effective resistance as seen by the battery is R = E/I = 12/6 = 2 ohms.
-- If you didn't know the voltage of the battery, you would calculate the
effective resistance of the parallel resistors in advance like this:
1/R = 1/4 + 1/4 = 1/2
R = 2 ohms.
When you connected them to a battery, the battery would agree.
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