Find the sum of the digits of 33333333334 to the second power?

first you multiply 33333333334 by 33333333334

(if its kinda hard to count these, they both have ten 3's, and one 4)

and then you should get this:

1111111111155555555556

(for this one, there are eleven 1's, ten 5's, and one 6)

then you add all these digits together, and should get this:

67

***p.s. the reason why it's not 1156 is because, in the order of operations, you have to solve the exponents (to the second power) before you can start adding***