How much heat is absorbed by a 59g iron skillet when its temperature rises from 10oC to 25oC?

410 J

First you need to find the specific heat capacity (c) for iron, which is 0.461 J/g-oC (https://www.engineersedge.com/materials/specific_heat_capacity_of_metals_13259.htm).

The equation to use is Q=m x c x delta t, where Q is energy, m is mass, c is specific heat, and delta t is change in temperature. Delta t = Tfinal - Tinitial = 25 oC - 10 oC = 15 oC.

Plug the known values into the equation and solve.

Q = 59 g x 0.461 J/g-oC x 15 oC = 410 J (rounded to two significant figures)