How much heat energy is absorbed when 171 g of ice melts?

To calculate the heat energy absorbed when 171 g of ice melts, we use the formula ( q = m \times L_f ), where ( L_f ) is the latent heat of fusion for ice, approximately 334 J/g. Therefore, the heat energy absorbed is ( q = 171 , \text{g} \times 334 , \text{J/g} = 57,054 , \text{J} ) or 57.1 kJ.