How many grams of hydrazine are needed to produce 96.0 of water?

To determine the grams of hydrazine (N2H4) needed to produce 96.0 grams of water (H2O), we start with the balanced chemical equation for the reaction: 2 N2H4 + 2 O2 → 4 H2O + N2. From this equation, we see that 2 moles of hydrazine produce 4 moles of water. The molar mass of water is approximately 18 g/mol, so 96.0 g of water corresponds to 5.33 moles of water. This means 2.67 moles of hydrazine are required, which equals about 66.3 grams of hydrazine (with a molar mass of 32.05 g/mol).