How many grams of sodium does a 5.35 g sample of sodium bromide contain?

All you really need here is a ratio of molar masses, ie molar mass of Na/molar mass of NaBr

So look at your Periodic Table and is says:

Na = 23g/mol

Br = 80g/mol

therefore

NaBr = 103g/mol

so from this, you actually know a percentage of Sodium to Bromine, correct me if I'm wrong, someone else please but just take:

(23g/mol)/103g/mol = 22.3% of you NaBr is actually Na,

so take 5.35g * 0.223 and you get:

1.19g of Na in your NaBr

Hope that helps.

Cheers