Why The current ratio of an ideal transformer is inversely related to the turns ratio?

The current ratio of an ideal transformer is inversely related to the turns ratio because of the principle of conservation of power. In an ideal transformer, the input power (primary side) must equal the output power (secondary side), leading to the relationship ( V_p I_p = V_s I_s ), where ( V ) represents voltage and ( I ) represents current. Since the voltage ratio is equal to the turns ratio (( \frac{V_p}{V_s} = \frac{N_p}{N_s} )), the current ratio is inversely proportional: ( \frac{I_s}{I_p} = \frac{N_p}{N_s} ). Thus, as the turns ratio increases, the current on the secondary side decreases, and vice versa.