The graph of the equation given below is a circle. What is the length of the radius of the circle (x plus 4)2 plus (y - 7)2 132?

The equation of the circle is given as ((x + 4)^2 + (y - 7)^2 = 132). In the standard form of a circle ((x - h)^2 + (y - k)^2 = r^2), the radius (r) can be determined from the right side of the equation. Here, (r^2 = 132), so the radius (r = \sqrt{132} = 2\sqrt{33}). Thus, the length of the radius of the circle is (2\sqrt{33}).