First find moles hydrogen gas.
20 grams H2 (1 mole H2/2.016 grams)
= 9.921 moles H2
Now, the ideal gas equation.
PV = nRT
(1 atm)(volume L) = (9.921 moles H2)(0.08206 L*atm/mol*K)(298.15 K)
Volume of hydrogen gas = 243 Liters
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