What refund amount represents the thirty-fifth percentile of tax returns when given an average income of 3036 and a standard deviation of 950?

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Answer

1062704

2026-04-19 06:11

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Assuming a normal distribution of incomes: 2672

z = ( 2672 - 3036 ) / 950 = -0.383157895

Pr{z<=-0.383157895}~=0.3508013475 or 35%

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